2x^(2/3)-13x^(1/3)-7=0

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Solution for 2x^(2/3)-13x^(1/3)-7=0 equation: 


x in (-oo:+oo)

2*x^(2/3)-(13*x^(1/3))-7 = 0

2*x^(2/3)-13*x^(1/3)-7 = 0

t_1 = x^(1/3)

2*t_1^2-13*t_1^1-7 = 0

2*t_1^2-13*t_1-7 = 0

DELTA = (-13)^2-(-7*2*4)

DELTA = 225

DELTA > 0

t_1 = (225^(1/2)+13)/(2*2) or t_1 = (13-225^(1/2))/(2*2)

t_1 = 7 or t_1 = -1/2

t_1 = -1/2

x^(1/3)+1/2 = 0

1*x^(1/3) = -1/2 // : 1

x^(1/3) = -1/2

( -1/2 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 7

x^(1/3)-7 = 0

1*x^(1/3) = 7 // : 1

x^(1/3) = 7

x^(1/3) = 7 // ^ 3

x = 343

x = 343

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